64x^2-35=-16x

Solution for 64x^2-35=-16x equation:

64x^2-35=-16x

We move all terms to the left:

64x^2-35-(-16x)=0

We get rid of parentheses

64x^2+16x-35=0

a = 64; b = 16; c = -35;
Δ = b2-4ac
Δ = 162-4·64·(-35)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-96}{2*64}=\frac{-112}{128}
=-7/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+96}{2*64}=\frac{80}{128}
=5/8
$